Metamath Proof Explorer


Theorem rev0

Description: The empty word is its own reverse. (Contributed by Stefan O'Rear, 26-Aug-2015)

Ref Expression
Assertion rev0 ( reverse ‘ ∅ ) = ∅

Proof

Step Hyp Ref Expression
1 wrd0 ⊢ ∅ ∈ Word V
2 revlen ⊢ ( ∅ ∈ Word V → ( ♯ ‘ ( reverse ‘ ∅ ) ) = ( ♯ ‘ ∅ ) )
3 1 2 ax-mp ⊢ ( ♯ ‘ ( reverse ‘ ∅ ) ) = ( ♯ ‘ ∅ )
4 hash0 ⊢ ( ♯ ‘ ∅ ) = 0
5 3 4 eqtri ⊢ ( ♯ ‘ ( reverse ‘ ∅ ) ) = 0
6 fvex ⊢ ( reverse ‘ ∅ ) ∈ V
7 hasheq0 ⊢ ( ( reverse ‘ ∅ ) ∈ V → ( ( ♯ ‘ ( reverse ‘ ∅ ) ) = 0 ↔ ( reverse ‘ ∅ ) = ∅ ) )
8 6 7 ax-mp ⊢ ( ( ♯ ‘ ( reverse ‘ ∅ ) ) = 0 ↔ ( reverse ‘ ∅ ) = ∅ )
9 5 8 mpbi ⊢ ( reverse ‘ ∅ ) = ∅