Metamath Proof Explorer


Theorem rhmsub

Description: Ring homomorphisms preserve subtraction. (Contributed by Jeff Madsen, 15-Jun-2011) (Revised by AV, 10-Jan-2025)

Ref Expression
Hypotheses rhmsub.x ⊢ 𝑋 = ( Base ‘ 𝑅 )
rhmsub.m ⊢ − = ( -g ‘ 𝑅 )
rhmsub.n ⊢ 𝑁 = ( -g ‘ 𝑆 )
Assertion rhmsub ( ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐹 ‘ ( 𝐴 − 𝐵 ) ) = ( ( 𝐹 ‘ 𝐴 ) 𝑁 ( 𝐹 ‘ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 rhmsub.x ⊢ 𝑋 = ( Base ‘ 𝑅 )
2 rhmsub.m ⊢ − = ( -g ‘ 𝑅 )
3 rhmsub.n ⊢ 𝑁 = ( -g ‘ 𝑆 )
4 rhmghm ⊢ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) )
5 1 2 3 ghmsub ⊢ ( ( 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐹 ‘ ( 𝐴 − 𝐵 ) ) = ( ( 𝐹 ‘ 𝐴 ) 𝑁 ( 𝐹 ‘ 𝐵 ) ) )
6 4 5 syl3an1 ⊢ ( ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐹 ‘ ( 𝐴 − 𝐵 ) ) = ( ( 𝐹 ‘ 𝐴 ) 𝑁 ( 𝐹 ‘ 𝐵 ) ) )