Metamath Proof Explorer


Theorem rncoss

Description: Range of a composition. (Contributed by NM, 19-Mar-1998)

Ref Expression
Assertion rncoss ran ( 𝐴 ∘ 𝐵 ) ⊆ ran 𝐴

Proof

Step Hyp Ref Expression
1 dmcoss ⊢ dom ( ◡ 𝐵 ∘ ◡ 𝐴 ) ⊆ dom ◡ 𝐴
2 df-rn ⊢ ran ( 𝐴 ∘ 𝐵 ) = dom ◡ ( 𝐴 ∘ 𝐵 )
3 cnvco ⊢ ◡ ( 𝐴 ∘ 𝐵 ) = ( ◡ 𝐵 ∘ ◡ 𝐴 )
4 3 dmeqi ⊢ dom ◡ ( 𝐴 ∘ 𝐵 ) = dom ( ◡ 𝐵 ∘ ◡ 𝐴 )
5 2 4 eqtri ⊢ ran ( 𝐴 ∘ 𝐵 ) = dom ( ◡ 𝐵 ∘ ◡ 𝐴 )
6 df-rn ⊢ ran 𝐴 = dom ◡ 𝐴
7 1 5 6 3sstr4i ⊢ ran ( 𝐴 ∘ 𝐵 ) ⊆ ran 𝐴