Metamath Proof Explorer


Theorem rngohomcl

Description: Closure law for a ring homomorphism. (Contributed by Jeff Madsen, 3-Jan-2011)

Ref Expression
Hypotheses rnghomf.1 𝐺 = ( 1st𝑅 )
rnghomf.2 𝑋 = ran 𝐺
rnghomf.3 𝐽 = ( 1st𝑆 )
rnghomf.4 𝑌 = ran 𝐽
Assertion rngohomcl ( ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ) ∧ 𝐴𝑋 ) → ( 𝐹𝐴 ) ∈ 𝑌 )

Proof

Step Hyp Ref Expression
1 rnghomf.1 𝐺 = ( 1st𝑅 )
2 rnghomf.2 𝑋 = ran 𝐺
3 rnghomf.3 𝐽 = ( 1st𝑆 )
4 rnghomf.4 𝑌 = ran 𝐽
5 1 2 3 4 rngohomf ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ) → 𝐹 : 𝑋𝑌 )
6 5 ffvelrnda ( ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ) ∧ 𝐴𝑋 ) → ( 𝐹𝐴 ) ∈ 𝑌 )