Metamath Proof Explorer
Description: Closure law for a ring homomorphism. (Contributed by Jeff Madsen, 3-Jan-2011)
|
|
Ref |
Expression |
|
Hypotheses |
rnghomf.1 |
⊢ 𝐺 = ( 1st ‘ 𝑅 ) |
|
|
rnghomf.2 |
⊢ 𝑋 = ran 𝐺 |
|
|
rnghomf.3 |
⊢ 𝐽 = ( 1st ‘ 𝑆 ) |
|
|
rnghomf.4 |
⊢ 𝑌 = ran 𝐽 |
|
Assertion |
rngohomcl |
⊢ ( ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ) ∧ 𝐴 ∈ 𝑋 ) → ( 𝐹 ‘ 𝐴 ) ∈ 𝑌 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
rnghomf.1 |
⊢ 𝐺 = ( 1st ‘ 𝑅 ) |
2 |
|
rnghomf.2 |
⊢ 𝑋 = ran 𝐺 |
3 |
|
rnghomf.3 |
⊢ 𝐽 = ( 1st ‘ 𝑆 ) |
4 |
|
rnghomf.4 |
⊢ 𝑌 = ran 𝐽 |
5 |
1 2 3 4
|
rngohomf |
⊢ ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ) → 𝐹 : 𝑋 ⟶ 𝑌 ) |
6 |
5
|
ffvelrnda |
⊢ ( ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ) ∧ 𝐴 ∈ 𝑋 ) → ( 𝐹 ‘ 𝐴 ) ∈ 𝑌 ) |