Metamath Proof Explorer


Theorem rngoisohom

Description: A ring isomorphism is a ring homomorphism. (Contributed by Jeff Madsen, 16-Jun-2011)

Ref Expression
Assertion rngoisohom ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngIso 𝑆 ) ) → 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) )

Proof

Step Hyp Ref Expression
1 eqid ( 1st𝑅 ) = ( 1st𝑅 )
2 eqid ran ( 1st𝑅 ) = ran ( 1st𝑅 )
3 eqid ( 1st𝑆 ) = ( 1st𝑆 )
4 eqid ran ( 1st𝑆 ) = ran ( 1st𝑆 )
5 1 2 3 4 isrngoiso ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ) → ( 𝐹 ∈ ( 𝑅 RngIso 𝑆 ) ↔ ( 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) ∧ 𝐹 : ran ( 1st𝑅 ) –1-1-onto→ ran ( 1st𝑆 ) ) ) )
6 5 simprbda ( ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ) ∧ 𝐹 ∈ ( 𝑅 RngIso 𝑆 ) ) → 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) )
7 6 3impa ( ( 𝑅 ∈ RingOps ∧ 𝑆 ∈ RingOps ∧ 𝐹 ∈ ( 𝑅 RngIso 𝑆 ) ) → 𝐹 ∈ ( 𝑅 RngHom 𝑆 ) )