Metamath Proof Explorer


Theorem rspa

Description: Restricted specialization. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Assertion rspa ( ( ∀ 𝑥𝐴 𝜑𝑥𝐴 ) → 𝜑 )

Proof

Step Hyp Ref Expression
1 rsp ( ∀ 𝑥𝐴 𝜑 → ( 𝑥𝐴𝜑 ) )
2 1 imp ( ( ∀ 𝑥𝐴 𝜑𝑥𝐴 ) → 𝜑 )