Metamath Proof Explorer


Theorem rspcdf

Description: Restricted specialization, using implicit substitution. (Contributed by Emmett Weisz, 16-Jan-2020)

Ref Expression
Hypotheses rspcdf.1 ⊢ Ⅎ 𝑥 𝜑
rspcdf.2 ⊢ Ⅎ 𝑥 𝜒
rspcdf.3 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
rspcdf.4 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → ( 𝜓 ↔ 𝜒 ) )
Assertion rspcdf ( 𝜑 → ( ∀ 𝑥 ∈ 𝐵 𝜓 → 𝜒 ) )

Proof

Step Hyp Ref Expression
1 rspcdf.1 ⊢ Ⅎ 𝑥 𝜑
2 rspcdf.2 ⊢ Ⅎ 𝑥 𝜒
3 rspcdf.3 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
4 rspcdf.4 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → ( 𝜓 ↔ 𝜒 ) )
5 4 ex ⊢ ( 𝜑 → ( 𝑥 = 𝐴 → ( 𝜓 ↔ 𝜒 ) ) )
6 1 5 alrimi ⊢ ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝐴 → ( 𝜓 ↔ 𝜒 ) ) )
7 2 rspct ⊢ ( ∀ 𝑥 ( 𝑥 = 𝐴 → ( 𝜓 ↔ 𝜒 ) ) → ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝜓 → 𝜒 ) ) )
8 6 3 7 sylc ⊢ ( 𝜑 → ( ∀ 𝑥 ∈ 𝐵 𝜓 → 𝜒 ) )