Metamath Proof Explorer


Theorem sb56

Description: Two equivalent ways of expressing the proper substitution of y for x in ph , when x and y are distinct, namely, alternate definitions sb5 and sb6 . Theorem 6.2 of Quine p. 40. The proof does not involve df-sb . The implication "to the left" is equs4 and does not require any disjoint variable condition (but the version with a disjoint variable condition, equs4v , requires fewer axioms). Theorem equs45f replaces the disjoint variable condition with a non-freeness hypothesis and equs5 replaces it with a distinctor as antecedent. (Contributed by NM, 14-Apr-2008) Revised to use equsexv in place of equsex in order to remove dependency on ax-13 . (Revised by BJ, 20-Dec-2020)

Ref Expression
Assertion sb56 ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )

Proof

Step Hyp Ref Expression
1 sb5 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
2 sb6 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
3 1 2 bitr3i ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )