Metamath Proof Explorer


Theorem sbcnel12g

Description: Distribute proper substitution through negated membership. (Contributed by Andrew Salmon, 18-Jun-2011)

Ref Expression
Assertion sbcnel12g ( 𝐴 ∈ 𝑉 → ( [ 𝐴 / 𝑥 ] 𝐵 ∉ 𝐶 ↔ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ∉ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 sbcng ⊢ ( 𝐴 ∈ 𝑉 → ( [ 𝐴 / 𝑥 ] ¬ 𝐵 ∈ 𝐶 ↔ ¬ [ 𝐴 / 𝑥 ] 𝐵 ∈ 𝐶 ) )
2 df-nel ⊢ ( 𝐵 ∉ 𝐶 ↔ ¬ 𝐵 ∈ 𝐶 )
3 2 sbcbii ⊢ ( [ 𝐴 / 𝑥 ] 𝐵 ∉ 𝐶 ↔ [ 𝐴 / 𝑥 ] ¬ 𝐵 ∈ 𝐶 )
4 df-nel ⊢ ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ∉ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ↔ ¬ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ∈ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 )
5 sbcel12 ⊢ ( [ 𝐴 / 𝑥 ] 𝐵 ∈ 𝐶 ↔ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ∈ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 )
6 4 5 xchbinxr ⊢ ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ∉ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ↔ ¬ [ 𝐴 / 𝑥 ] 𝐵 ∈ 𝐶 )
7 1 3 6 3bitr4g ⊢ ( 𝐴 ∈ 𝑉 → ( [ 𝐴 / 𝑥 ] 𝐵 ∉ 𝐶 ↔ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ∉ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) )