Metamath Proof Explorer


Theorem sbcov

Description: A composition law for substitution. Version of sbco with a disjoint variable condition using fewer axioms. (Contributed by NM, 14-May-1993) (Revised by GG, 7-Aug-2023) (Proof shortened by SN, 26-Aug-2025)

Ref Expression
Assertion sbcov ( [ 𝑦 / 𝑥 ] [ 𝑥 / 𝑦 ] 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sbequ12r ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑦 ] 𝜑𝜑 ) )
2 1 sbbiiev ( [ 𝑦 / 𝑥 ] [ 𝑥 / 𝑦 ] 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 )