Metamath Proof Explorer
Description: An equality theorem for substitution. (Contributed by NM, 2-Jun-1993)
(Proof shortened by Wolf Lammen, 23-Jun-2019)
|
|
Ref |
Expression |
|
Assertion |
sbequ12a |
⊢ ( 𝑥 = 𝑦 → ( [ 𝑦 / 𝑥 ] 𝜑 ↔ [ 𝑥 / 𝑦 ] 𝜑 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
sbequ12r |
⊢ ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑦 ] 𝜑 ↔ 𝜑 ) ) |
2 |
|
sbequ12 |
⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ [ 𝑦 / 𝑥 ] 𝜑 ) ) |
3 |
1 2
|
bitr2d |
⊢ ( 𝑥 = 𝑦 → ( [ 𝑦 / 𝑥 ] 𝜑 ↔ [ 𝑥 / 𝑦 ] 𝜑 ) ) |