Metamath Proof Explorer


Theorem sbievOLD

Description: Obsolete version of sbiev as of 24-Aug-2025. (Contributed by NM, 30-Jun-1994) (Revised by Wolf Lammen, 18-Jan-2023) Remove dependence on ax-10 and shorten proof. (Revised by BJ, 18-Jul-2023) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses sbiev.1 𝑥 𝜓
sbiev.2 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion sbievOLD ( [ 𝑦 / 𝑥 ] 𝜑𝜓 )

Proof

Step Hyp Ref Expression
1 sbiev.1 𝑥 𝜓
2 sbiev.2 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
3 sb6 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
4 1 2 equsalv ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )
5 3 4 bitri ( [ 𝑦 / 𝑥 ] 𝜑𝜓 )