Metamath Proof Explorer
Description: The slot for the scalar is not the slot for the base set in an extensible
structure. (Contributed by AV, 21-Oct-2024)
|
|
Ref |
Expression |
|
Assertion |
scandxnbasendx |
⊢ ( Scalar ‘ ndx ) ≠ ( Base ‘ ndx ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
1re |
⊢ 1 ∈ ℝ |
| 2 |
|
1lt5 |
⊢ 1 < 5 |
| 3 |
1 2
|
gtneii |
⊢ 5 ≠ 1 |
| 4 |
|
scandx |
⊢ ( Scalar ‘ ndx ) = 5 |
| 5 |
|
basendx |
⊢ ( Base ‘ ndx ) = 1 |
| 6 |
4 5
|
neeq12i |
⊢ ( ( Scalar ‘ ndx ) ≠ ( Base ‘ ndx ) ↔ 5 ≠ 1 ) |
| 7 |
3 6
|
mpbir |
⊢ ( Scalar ‘ ndx ) ≠ ( Base ‘ ndx ) |