Metamath Proof Explorer


Theorem sgn0

Description: The signum of 0 is 0. (Contributed by David A. Wheeler, 15-May-2015)

Ref Expression
Assertion sgn0 ( sgn ‘ 0 ) = 0

Proof

Step Hyp Ref Expression
1 0xr ⊢ 0 ∈ ℝ*
2 sgnval ⊢ ( 0 ∈ ℝ* → ( sgn ‘ 0 ) = if ( 0 = 0 , 0 , if ( 0 < 0 , - 1 , 1 ) ) )
3 1 2 ax-mp ⊢ ( sgn ‘ 0 ) = if ( 0 = 0 , 0 , if ( 0 < 0 , - 1 , 1 ) )
4 eqid ⊢ 0 = 0
5 4 iftruei ⊢ if ( 0 = 0 , 0 , if ( 0 < 0 , - 1 , 1 ) ) = 0
6 3 5 eqtri ⊢ ( sgn ‘ 0 ) = 0