Metamath Proof Explorer


Theorem shlej2i

Description: Add disjunct to both sides of Hilbert subspace ordering. (Contributed by NM, 19-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses shincl.1 ⊢ 𝐴 ∈ Sℋ
shincl.2 ⊢ 𝐵 ∈ Sℋ
shless.1 ⊢ 𝐶 ∈ Sℋ
Assertion shlej2i ( 𝐴 ⊆ 𝐵 → ( 𝐶 ∨ℋ 𝐴 ) ⊆ ( 𝐶 ∨ℋ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 shincl.1 ⊢ 𝐴 ∈ Sℋ
2 shincl.2 ⊢ 𝐵 ∈ Sℋ
3 shless.1 ⊢ 𝐶 ∈ Sℋ
4 1 2 3 shlej1i ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∨ℋ 𝐶 ) ⊆ ( 𝐵 ∨ℋ 𝐶 ) )
5 3 1 shjcomi ⊢ ( 𝐶 ∨ℋ 𝐴 ) = ( 𝐴 ∨ℋ 𝐶 )
6 3 2 shjcomi ⊢ ( 𝐶 ∨ℋ 𝐵 ) = ( 𝐵 ∨ℋ 𝐶 )
7 4 5 6 3sstr4g ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐶 ∨ℋ 𝐴 ) ⊆ ( 𝐶 ∨ℋ 𝐵 ) )