Metamath Proof Explorer
Description: Members of a subspace and its complement are orthogonal. (Contributed by NM, 10-Oct-1999) (New usage is discouraged.)
|
|
Ref |
Expression |
|
Assertion |
shocorth |
⊢ ( 𝐻 ∈ Sℋ → ( ( 𝐴 ∈ 𝐻 ∧ 𝐵 ∈ ( ⊥ ‘ 𝐻 ) ) → ( 𝐴 ·ih 𝐵 ) = 0 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
shss |
⊢ ( 𝐻 ∈ Sℋ → 𝐻 ⊆ ℋ ) |
2 |
|
ocorth |
⊢ ( 𝐻 ⊆ ℋ → ( ( 𝐴 ∈ 𝐻 ∧ 𝐵 ∈ ( ⊥ ‘ 𝐻 ) ) → ( 𝐴 ·ih 𝐵 ) = 0 ) ) |
3 |
1 2
|
syl |
⊢ ( 𝐻 ∈ Sℋ → ( ( 𝐴 ∈ 𝐻 ∧ 𝐵 ∈ ( ⊥ ‘ 𝐻 ) ) → ( 𝐴 ·ih 𝐵 ) = 0 ) ) |