Metamath Proof Explorer


Theorem shocorth

Description: Members of a subspace and its complement are orthogonal. (Contributed by NM, 10-Oct-1999) (New usage is discouraged.)

Ref Expression
Assertion shocorth ( 𝐻S → ( ( 𝐴𝐻𝐵 ∈ ( ⊥ ‘ 𝐻 ) ) → ( 𝐴 ·ih 𝐵 ) = 0 ) )

Proof

Step Hyp Ref Expression
1 shss ( 𝐻S𝐻 ⊆ ℋ )
2 ocorth ( 𝐻 ⊆ ℋ → ( ( 𝐴𝐻𝐵 ∈ ( ⊥ ‘ 𝐻 ) ) → ( 𝐴 ·ih 𝐵 ) = 0 ) )
3 1 2 syl ( 𝐻S → ( ( 𝐴𝐻𝐵 ∈ ( ⊥ ‘ 𝐻 ) ) → ( 𝐴 ·ih 𝐵 ) = 0 ) )