Metamath Proof Explorer


Theorem shsval3i

Description: An alternate way to express subspace sum. (Contributed by NM, 25-Nov-2004) (New usage is discouraged.)

Ref Expression
Hypotheses shlesb1.1 ⊢ 𝐴 ∈ Sℋ
shlesb1.2 ⊢ 𝐵 ∈ Sℋ
Assertion shsval3i ( 𝐴 +ℋ 𝐵 ) = ( span ‘ ( 𝐴 ∪ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 shlesb1.1 ⊢ 𝐴 ∈ Sℋ
2 shlesb1.2 ⊢ 𝐵 ∈ Sℋ
3 1 2 shsval2i ⊢ ( 𝐴 +ℋ 𝐵 ) = ∩ { 𝑥 ∈ Sℋ ∣ ( 𝐴 ∪ 𝐵 ) ⊆ 𝑥 }
4 1 shssii ⊢ 𝐴 ⊆ ℋ
5 2 shssii ⊢ 𝐵 ⊆ ℋ
6 4 5 unssi ⊢ ( 𝐴 ∪ 𝐵 ) ⊆ ℋ
7 spanval ⊢ ( ( 𝐴 ∪ 𝐵 ) ⊆ ℋ → ( span ‘ ( 𝐴 ∪ 𝐵 ) ) = ∩ { 𝑥 ∈ Sℋ ∣ ( 𝐴 ∪ 𝐵 ) ⊆ 𝑥 } )
8 6 7 ax-mp ⊢ ( span ‘ ( 𝐴 ∪ 𝐵 ) ) = ∩ { 𝑥 ∈ Sℋ ∣ ( 𝐴 ∪ 𝐵 ) ⊆ 𝑥 }
9 3 8 eqtr4i ⊢ ( 𝐴 +ℋ 𝐵 ) = ( span ‘ ( 𝐴 ∪ 𝐵 ) )