Description: Deduction eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019)
Ref | Expression | ||
---|---|---|---|
Hypothesis | simplrd.1 | ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) ∧ 𝜃 ) ) | |
Assertion | simplrd | ⊢ ( 𝜑 → 𝜒 ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | simplrd.1 | ⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜒 ) ∧ 𝜃 ) ) | |
2 | 1 | simpld | ⊢ ( 𝜑 → ( 𝜓 ∧ 𝜒 ) ) |
3 | 2 | simprd | ⊢ ( 𝜑 → 𝜒 ) |