Metamath Proof Explorer


Theorem spansnscl

Description: The subspace sum of a closed subspace and a one-dimensional subspace is closed. (Contributed by NM, 17-Dec-2004) (New usage is discouraged.)

Ref Expression
Assertion spansnscl ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ ℋ ) → ( 𝐴 +ℋ ( span ‘ { 𝐵 } ) ) ∈ Cℋ )

Proof

Step Hyp Ref Expression
1 spansnj ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ ℋ ) → ( 𝐴 +ℋ ( span ‘ { 𝐵 } ) ) = ( 𝐴 ∨ℋ ( span ‘ { 𝐵 } ) ) )
2 spansnch ⊢ ( 𝐵 ∈ ℋ → ( span ‘ { 𝐵 } ) ∈ Cℋ )
3 chjcl ⊢ ( ( 𝐴 ∈ Cℋ ∧ ( span ‘ { 𝐵 } ) ∈ Cℋ ) → ( 𝐴 ∨ℋ ( span ‘ { 𝐵 } ) ) ∈ Cℋ )
4 2 3 sylan2 ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ ℋ ) → ( 𝐴 ∨ℋ ( span ‘ { 𝐵 } ) ) ∈ Cℋ )
5 1 4 eqeltrd ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ ℋ ) → ( 𝐴 +ℋ ( span ‘ { 𝐵 } ) ) ∈ Cℋ )