Metamath Proof Explorer


Theorem spcdv

Description: Rule of specialization, using implicit substitution. Analogous to rspcdv . (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypotheses spcimdv.1 ( 𝜑𝐴𝐵 )
spcdv.2 ( ( 𝜑𝑥 = 𝐴 ) → ( 𝜓𝜒 ) )
Assertion spcdv ( 𝜑 → ( ∀ 𝑥 𝜓𝜒 ) )

Proof

Step Hyp Ref Expression
1 spcimdv.1 ( 𝜑𝐴𝐵 )
2 spcdv.2 ( ( 𝜑𝑥 = 𝐴 ) → ( 𝜓𝜒 ) )
3 2 biimpd ( ( 𝜑𝑥 = 𝐴 ) → ( 𝜓𝜒 ) )
4 1 3 spcimdv ( 𝜑 → ( ∀ 𝑥 𝜓𝜒 ) )