Metamath Proof Explorer


Theorem spei

Description: Inference from existential specialization, using implicit substitution. Remove a distinct variable constraint. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker speiv if possible. (Contributed by NM, 19-Aug-1993) (Proof shortened by Wolf Lammen, 12-May-2018) (New usage is discouraged.)

Ref Expression
Hypotheses spei.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
spei.2 𝜓
Assertion spei 𝑥 𝜑

Proof

Step Hyp Ref Expression
1 spei.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
2 spei.2 𝜓
3 ax6e 𝑥 𝑥 = 𝑦
4 2 1 mpbiri ( 𝑥 = 𝑦𝜑 )
5 3 4 eximii 𝑥 𝜑