Metamath Proof Explorer


Theorem speimfwALT

Description: Alternate proof of speimfw (longer compressed proof, but fewer essential steps). (Contributed by NM, 23-Apr-2017) (Proof shortened by Wolf Lammen, 5-Aug-2017) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis speimfw.2 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 → 𝜓 ) )
Assertion speimfwALT ( ¬ ∀ 𝑥 ¬ 𝑥 = 𝑦 → ( ∀ 𝑥 𝜑 → ∃ 𝑥 𝜓 ) )

Proof

Step Hyp Ref Expression
1 speimfw.2 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 → 𝜓 ) )
2 1 eximi ⊢ ( ∃ 𝑥 𝑥 = 𝑦 → ∃ 𝑥 ( 𝜑 → 𝜓 ) )
3 df-ex ⊢ ( ∃ 𝑥 𝑥 = 𝑦 ↔ ¬ ∀ 𝑥 ¬ 𝑥 = 𝑦 )
4 19.35 ⊢ ( ∃ 𝑥 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 𝜑 → ∃ 𝑥 𝜓 ) )
5 2 3 4 3imtr3i ⊢ ( ¬ ∀ 𝑥 ¬ 𝑥 = 𝑦 → ( ∀ 𝑥 𝜑 → ∃ 𝑥 𝜓 ) )