Metamath Proof Explorer


Theorem speiv

Description: Inference from existential specialization. (Contributed by NM, 19-Aug-1993) (Revised by Wolf Lammen, 22-Oct-2023)

Ref Expression
Hypotheses speiv.1 ( 𝑥 = 𝑦 → ( 𝜓𝜑 ) )
speiv.2 𝜓
Assertion speiv 𝑥 𝜑

Proof

Step Hyp Ref Expression
1 speiv.1 ( 𝑥 = 𝑦 → ( 𝜓𝜑 ) )
2 speiv.2 𝜓
3 2 hbth ( 𝜓 → ∀ 𝑥 𝜓 )
4 3 1 spimew ( 𝜓 → ∃ 𝑥 𝜑 )
5 2 4 ax-mp 𝑥 𝜑