Metamath Proof Explorer


Theorem speivw

Description: Version of spei with a disjoint variable condition, which does not require ax-13 (neither ax-7 nor ax-12 ). (Contributed by BJ, 31-May-2019)

Ref Expression
Hypotheses speivw.1 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
speivw.2 ⊢ 𝜓
Assertion speivw ∃ 𝑥 𝜑

Proof

Step Hyp Ref Expression
1 speivw.1 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
2 speivw.2 ⊢ 𝜓
3 1 biimprd ⊢ ( 𝑥 = 𝑦 → ( 𝜓 → 𝜑 ) )
4 3 2 speiv ⊢ ∃ 𝑥 𝜑