Metamath Proof Explorer


Theorem spimfv

Description: Specialization, using implicit substitution. Version of spim with a disjoint variable condition, which does not require ax-13 . See spimvw for a version with two disjoint variable conditions, requiring fewer axioms, and spimv for another variant. (Contributed by NM, 10-Jan-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses spimfv.nf 𝑥 𝜓
spimfv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion spimfv ( ∀ 𝑥 𝜑𝜓 )

Proof

Step Hyp Ref Expression
1 spimfv.nf 𝑥 𝜓
2 spimfv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
3 ax6ev 𝑥 𝑥 = 𝑦
4 3 2 eximii 𝑥 ( 𝜑𝜓 )
5 1 4 19.36i ( ∀ 𝑥 𝜑𝜓 )