Metamath Proof Explorer


Theorem spsbcd

Description: Specialization: if a formula is true for all sets, it is true for any class which is a set. Similar to Theorem 6.11 of Quine p. 44. See also stdpc4 and rspsbc . (Contributed by Mario Carneiro, 9-Feb-2017)

Ref Expression
Hypotheses spsbcd.1 ( 𝜑𝐴𝑉 )
spsbcd.2 ( 𝜑 → ∀ 𝑥 𝜓 )
Assertion spsbcd ( 𝜑[ 𝐴 / 𝑥 ] 𝜓 )

Proof

Step Hyp Ref Expression
1 spsbcd.1 ( 𝜑𝐴𝑉 )
2 spsbcd.2 ( 𝜑 → ∀ 𝑥 𝜓 )
3 spsbc ( 𝐴𝑉 → ( ∀ 𝑥 𝜓[ 𝐴 / 𝑥 ] 𝜓 ) )
4 1 2 3 sylc ( 𝜑[ 𝐴 / 𝑥 ] 𝜓 )