Metamath Proof Explorer
		
		
		
		Description:  The square root of 9 is 3.  (Contributed by NM, 11-May-2004)
		
			
				
					|  |  | Ref | Expression | 
				
					|  | Assertion | sqrt9 | ⊢  ( √ ‘ 9 )  =  3 | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | sq3 | ⊢ ( 3 ↑ 2 )  =  9 | 
						
							| 2 | 1 | fveq2i | ⊢ ( √ ‘ ( 3 ↑ 2 ) )  =  ( √ ‘ 9 ) | 
						
							| 3 |  | 3re | ⊢ 3  ∈  ℝ | 
						
							| 4 |  | 0re | ⊢ 0  ∈  ℝ | 
						
							| 5 |  | 3pos | ⊢ 0  <  3 | 
						
							| 6 | 4 3 5 | ltleii | ⊢ 0  ≤  3 | 
						
							| 7 |  | sqrtsq | ⊢ ( ( 3  ∈  ℝ  ∧  0  ≤  3 )  →  ( √ ‘ ( 3 ↑ 2 ) )  =  3 ) | 
						
							| 8 | 3 6 7 | mp2an | ⊢ ( √ ‘ ( 3 ↑ 2 ) )  =  3 | 
						
							| 9 | 2 8 | eqtr3i | ⊢ ( √ ‘ 9 )  =  3 |