Metamath Proof Explorer


Theorem sqrtth

Description: Square root theorem over the complex numbers. Theorem I.35 of Apostol p. 29. (Contributed by Mario Carneiro, 10-Jul-2013)

Ref Expression
Assertion sqrtth ( 𝐴 ∈ ℂ → ( ( √ ‘ 𝐴 ) ↑ 2 ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 sqrtthlem ( 𝐴 ∈ ℂ → ( ( ( √ ‘ 𝐴 ) ↑ 2 ) = 𝐴 ∧ 0 ≤ ( ℜ ‘ ( √ ‘ 𝐴 ) ) ∧ ( i · ( √ ‘ 𝐴 ) ) ∉ ℝ+ ) )
2 1 simp1d ( 𝐴 ∈ ℂ → ( ( √ ‘ 𝐴 ) ↑ 2 ) = 𝐴 )