Metamath Proof Explorer


Theorem ss2rabdf

Description: Deduction of restricted abstraction subclass from implication. (Contributed by Glauco Siliprandi, 21-Dec-2024)

Ref Expression
Hypotheses ss2rabdf.1 ⊢ Ⅎ 𝑥 𝜑
ss2rabdf.2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝜓 → 𝜒 ) )
Assertion ss2rabdf ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ { 𝑥 ∈ 𝐴 ∣ 𝜒 } )

Proof

Step Hyp Ref Expression
1 ss2rabdf.1 ⊢ Ⅎ 𝑥 𝜑
2 ss2rabdf.2 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝜓 → 𝜒 ) )
3 1 2 ralrimia ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝐴 ( 𝜓 → 𝜒 ) )
4 3 ss2rabd ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } ⊆ { 𝑥 ∈ 𝐴 ∣ 𝜒 } )