Metamath Proof Explorer


Theorem sscrel

Description: The subcategory subset relation is a relation. (Contributed by Mario Carneiro, 6-Jan-2017)

Ref Expression
Assertion sscrel Rel ⊆cat

Proof

Step Hyp Ref Expression
1 df-ssc cat = { ⟨ , 𝑗 ⟩ ∣ ∃ 𝑡 ( 𝑗 Fn ( 𝑡 × 𝑡 ) ∧ ∃ 𝑠 ∈ 𝒫 𝑡 X 𝑥 ∈ ( 𝑠 × 𝑠 ) 𝒫 ( 𝑗𝑥 ) ) }
2 1 relopabiv Rel ⊆cat