Metamath Proof Explorer


Theorem sselid

Description: Membership inference from subclass relationship. (Contributed by NM, 25-Jun-2014)

Ref Expression
Hypotheses sseli.1 𝐴𝐵
sselid.2 ( 𝜑𝐶𝐴 )
Assertion sselid ( 𝜑𝐶𝐵 )

Proof

Step Hyp Ref Expression
1 sseli.1 𝐴𝐵
2 sselid.2 ( 𝜑𝐶𝐴 )
3 1 sseli ( 𝐶𝐴𝐶𝐵 )
4 2 3 syl ( 𝜑𝐶𝐵 )