Metamath Proof Explorer
Description: Membership inference from subclass relationship. (Contributed by NM, 25-Jun-2014)
|
|
Ref |
Expression |
|
Hypotheses |
sseli.1 |
⊢ 𝐴 ⊆ 𝐵 |
|
|
sselid.2 |
⊢ ( 𝜑 → 𝐶 ∈ 𝐴 ) |
|
Assertion |
sselid |
⊢ ( 𝜑 → 𝐶 ∈ 𝐵 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sseli.1 |
⊢ 𝐴 ⊆ 𝐵 |
| 2 |
|
sselid.2 |
⊢ ( 𝜑 → 𝐶 ∈ 𝐴 ) |
| 3 |
1
|
sseli |
⊢ ( 𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵 ) |
| 4 |
2 3
|
syl |
⊢ ( 𝜑 → 𝐶 ∈ 𝐵 ) |