Metamath Proof Explorer
Description: A subclass of an empty class is empty. (Contributed by NM, 7-Mar-2007)
(Proof shortened by Andrew Salmon, 26-Jun-2011)
|
|
Ref |
Expression |
|
Assertion |
sseq0 |
⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 = ∅ ) → 𝐴 = ∅ ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
sseq2 |
⊢ ( 𝐵 = ∅ → ( 𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ ∅ ) ) |
2 |
|
ss0 |
⊢ ( 𝐴 ⊆ ∅ → 𝐴 = ∅ ) |
3 |
1 2
|
syl6bi |
⊢ ( 𝐵 = ∅ → ( 𝐴 ⊆ 𝐵 → 𝐴 = ∅ ) ) |
4 |
3
|
impcom |
⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 = ∅ ) → 𝐴 = ∅ ) |