Metamath Proof Explorer
Description: Substitution of equality into a subclass relationship. (Contributed by NM, 28-Jul-1995)
|
|
Ref |
Expression |
|
Hypotheses |
sseqtr.1 |
⊢ 𝐴 ⊆ 𝐵 |
|
|
sseqtr.2 |
⊢ 𝐵 = 𝐶 |
|
Assertion |
sseqtri |
⊢ 𝐴 ⊆ 𝐶 |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sseqtr.1 |
⊢ 𝐴 ⊆ 𝐵 |
| 2 |
|
sseqtr.2 |
⊢ 𝐵 = 𝐶 |
| 3 |
2
|
sseq2i |
⊢ ( 𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐶 ) |
| 4 |
1 3
|
mpbi |
⊢ 𝐴 ⊆ 𝐶 |