Metamath Proof Explorer
Description: Subclass transitivity deduction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011)
|
|
Ref |
Expression |
|
Hypotheses |
sseqtrid.1 |
⊢ 𝐵 ⊆ 𝐴 |
|
|
sseqtrid.2 |
⊢ ( 𝜑 → 𝐴 = 𝐶 ) |
|
Assertion |
sseqtrid |
⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sseqtrid.1 |
⊢ 𝐵 ⊆ 𝐴 |
| 2 |
|
sseqtrid.2 |
⊢ ( 𝜑 → 𝐴 = 𝐶 ) |
| 3 |
1
|
a1i |
⊢ ( 𝜑 → 𝐵 ⊆ 𝐴 ) |
| 4 |
3 2
|
sseqtrd |
⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 ) |