Metamath Proof Explorer


Theorem sseqtrrdi

Description: A chained subclass and equality deduction. (Contributed by NM, 25-Apr-2004)

Ref Expression
Hypotheses sseqtrrdi.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
sseqtrrdi.2 ⊢ 𝐶 = 𝐵
Assertion sseqtrrdi ( 𝜑 → 𝐴 ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 sseqtrrdi.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
2 sseqtrrdi.2 ⊢ 𝐶 = 𝐵
3 2 eqcomi ⊢ 𝐵 = 𝐶
4 1 3 sseqtrdi ⊢ ( 𝜑 → 𝐴 ⊆ 𝐶 )