Metamath Proof Explorer
Description: Substitution of equality into a subclass relationship. (Contributed by NM, 4-Apr-1995)
|
|
Ref |
Expression |
|
Hypotheses |
sseqtrri.1 |
⊢ 𝐴 ⊆ 𝐵 |
|
|
sseqtrri.2 |
⊢ 𝐶 = 𝐵 |
|
Assertion |
sseqtrri |
⊢ 𝐴 ⊆ 𝐶 |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sseqtrri.1 |
⊢ 𝐴 ⊆ 𝐵 |
| 2 |
|
sseqtrri.2 |
⊢ 𝐶 = 𝐵 |
| 3 |
2
|
eqcomi |
⊢ 𝐵 = 𝐶 |
| 4 |
1 3
|
sseqtri |
⊢ 𝐴 ⊆ 𝐶 |