Metamath Proof Explorer


Theorem ssinss2d

Description: Intersection preserves subclass relationship. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Hypothesis ssinss2d.1 ⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 )
Assertion ssinss2d ( 𝜑 → ( 𝐴 ∩ 𝐵 ) ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 ssinss2d.1 ⊢ ( 𝜑 → 𝐵 ⊆ 𝐶 )
2 incom ⊢ ( 𝐴 ∩ 𝐵 ) = ( 𝐵 ∩ 𝐴 )
3 1 ssinss1d ⊢ ( 𝜑 → ( 𝐵 ∩ 𝐴 ) ⊆ 𝐶 )
4 2 3 eqsstrid ⊢ ( 𝜑 → ( 𝐴 ∩ 𝐵 ) ⊆ 𝐶 )