Metamath Proof Explorer


Theorem ssn0rex

Description: There is an element in a class with a nonempty subclass which is an element of the subclass. (Contributed by AV, 17-Dec-2020)

Ref Expression
Assertion ssn0rex ( ( 𝐴𝐵𝐴 ≠ ∅ ) → ∃ 𝑥𝐵 𝑥𝐴 )

Proof

Step Hyp Ref Expression
1 ssrexv ( 𝐴𝐵 → ( ∃ 𝑥𝐴 𝑥𝐴 → ∃ 𝑥𝐵 𝑥𝐴 ) )
2 n0rex ( 𝐴 ≠ ∅ → ∃ 𝑥𝐴 𝑥𝐴 )
3 1 2 impel ( ( 𝐴𝐵𝐴 ≠ ∅ ) → ∃ 𝑥𝐵 𝑥𝐴 )