Metamath Proof Explorer
Description: If a class is not in another class, it is also not in a subclass of that
class. Deduction form. (Contributed by David Moews, 1-May-2017)
|
|
Ref |
Expression |
|
Hypothesis |
ssneld.1 |
⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 ) |
|
Assertion |
ssneld |
⊢ ( 𝜑 → ( ¬ 𝐶 ∈ 𝐵 → ¬ 𝐶 ∈ 𝐴 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ssneld.1 |
⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 ) |
2 |
1
|
sseld |
⊢ ( 𝜑 → ( 𝐶 ∈ 𝐴 → 𝐶 ∈ 𝐵 ) ) |
3 |
2
|
con3d |
⊢ ( 𝜑 → ( ¬ 𝐶 ∈ 𝐵 → ¬ 𝐶 ∈ 𝐴 ) ) |