Metamath Proof Explorer
Description: If an element is not in a class, it is also not in a subclass of that
class. Deduction form. (Contributed by David Moews, 1-May-2017)
|
|
Ref |
Expression |
|
Hypotheses |
ssneld.1 |
⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 ) |
|
|
ssneldd.2 |
⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐵 ) |
|
Assertion |
ssneldd |
⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐴 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
ssneld.1 |
⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 ) |
2 |
|
ssneldd.2 |
⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐵 ) |
3 |
1
|
ssneld |
⊢ ( 𝜑 → ( ¬ 𝐶 ∈ 𝐵 → ¬ 𝐶 ∈ 𝐴 ) ) |
4 |
2 3
|
mpd |
⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐴 ) |