Metamath Proof Explorer


Theorem ssneldd

Description: If an element is not in a class, it is also not in a subclass of that class. Deduction form. (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypotheses ssneld.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
ssneldd.2 ⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐵 )
Assertion ssneldd ( 𝜑 → ¬ 𝐶 ∈ 𝐴 )

Proof

Step Hyp Ref Expression
1 ssneld.1 ⊢ ( 𝜑 → 𝐴 ⊆ 𝐵 )
2 ssneldd.2 ⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐵 )
3 1 ssneld ⊢ ( 𝜑 → ( ¬ 𝐶 ∈ 𝐵 → ¬ 𝐶 ∈ 𝐴 ) )
4 2 3 mpd ⊢ ( 𝜑 → ¬ 𝐶 ∈ 𝐴 )