Metamath Proof Explorer


Theorem sspw

Description: The powerclass preserves inclusion. See sspwb for the biconditional version. (Contributed by NM, 13-Oct-1996) Extract forward implication of sspwb since it requires fewer axioms. (Revised by BJ, 13-Apr-2024)

Ref Expression
Assertion sspw ( 𝐴 ⊆ 𝐵 → 𝒫 𝐴 ⊆ 𝒫 𝐵 )

Proof

Step Hyp Ref Expression
1 sstr2 ⊢ ( 𝑥 ⊆ 𝐴 → ( 𝐴 ⊆ 𝐵 → 𝑥 ⊆ 𝐵 ) )
2 1 com12 ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝑥 ⊆ 𝐴 → 𝑥 ⊆ 𝐵 ) )
3 velpw ⊢ ( 𝑥 ∈ 𝒫 𝐴 ↔ 𝑥 ⊆ 𝐴 )
4 velpw ⊢ ( 𝑥 ∈ 𝒫 𝐵 ↔ 𝑥 ⊆ 𝐵 )
5 2 3 4 3imtr4g ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝑥 ∈ 𝒫 𝐴 → 𝑥 ∈ 𝒫 𝐵 ) )
6 5 ssrdv ⊢ ( 𝐴 ⊆ 𝐵 → 𝒫 𝐴 ⊆ 𝒫 𝐵 )