Metamath Proof Explorer


Theorem sspwb

Description: The powerclass construction preserves and reflects inclusion. Classes are subclasses if and only if their power classes are subclasses. Exercise 18 of TakeutiZaring p. 18. (Contributed by NM, 13-Oct-1996)

Ref Expression
Assertion sspwb ( 𝐴 ⊆ 𝐵 ↔ 𝒫 𝐴 ⊆ 𝒫 𝐵 )

Proof

Step Hyp Ref Expression
1 sspw ⊢ ( 𝐴 ⊆ 𝐵 → 𝒫 𝐴 ⊆ 𝒫 𝐵 )
2 ssel ⊢ ( 𝒫 𝐴 ⊆ 𝒫 𝐵 → ( { 𝑥 } ∈ 𝒫 𝐴 → { 𝑥 } ∈ 𝒫 𝐵 ) )
3 vsnex ⊢ { 𝑥 } ∈ V
4 3 elpw ⊢ ( { 𝑥 } ∈ 𝒫 𝐴 ↔ { 𝑥 } ⊆ 𝐴 )
5 vex ⊢ 𝑥 ∈ V
6 5 snss ⊢ ( 𝑥 ∈ 𝐴 ↔ { 𝑥 } ⊆ 𝐴 )
7 4 6 bitr4i ⊢ ( { 𝑥 } ∈ 𝒫 𝐴 ↔ 𝑥 ∈ 𝐴 )
8 3 elpw ⊢ ( { 𝑥 } ∈ 𝒫 𝐵 ↔ { 𝑥 } ⊆ 𝐵 )
9 5 snss ⊢ ( 𝑥 ∈ 𝐵 ↔ { 𝑥 } ⊆ 𝐵 )
10 8 9 bitr4i ⊢ ( { 𝑥 } ∈ 𝒫 𝐵 ↔ 𝑥 ∈ 𝐵 )
11 2 7 10 3imtr3g ⊢ ( 𝒫 𝐴 ⊆ 𝒫 𝐵 → ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) )
12 11 ssrdv ⊢ ( 𝒫 𝐴 ⊆ 𝒫 𝐵 → 𝐴 ⊆ 𝐵 )
13 1 12 impbii ⊢ ( 𝐴 ⊆ 𝐵 ↔ 𝒫 𝐴 ⊆ 𝒫 𝐵 )