Metamath Proof Explorer


Theorem subgbas

Description: The base of the restricted group in a subgroup. (Contributed by Mario Carneiro, 2-Dec-2014)

Ref Expression
Hypothesis subggrp.h 𝐻 = ( 𝐺s 𝑆 )
Assertion subgbas ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) → 𝑆 = ( Base ‘ 𝐻 ) )

Proof

Step Hyp Ref Expression
1 subggrp.h 𝐻 = ( 𝐺s 𝑆 )
2 eqid ( Base ‘ 𝐺 ) = ( Base ‘ 𝐺 )
3 2 subgss ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) → 𝑆 ⊆ ( Base ‘ 𝐺 ) )
4 1 2 ressbas2 ( 𝑆 ⊆ ( Base ‘ 𝐺 ) → 𝑆 = ( Base ‘ 𝐻 ) )
5 3 4 syl ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) → 𝑆 = ( Base ‘ 𝐻 ) )