Metamath Proof Explorer


Theorem subgss

Description: A subgroup is a subset. (Contributed by Mario Carneiro, 2-Dec-2014)

Ref Expression
Hypothesis issubg.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
Assertion subgss ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) → 𝑆 ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 issubg.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
2 1 issubg ⊢ ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) ↔ ( 𝐺 ∈ Grp ∧ 𝑆 ⊆ 𝐵 ∧ ( 𝐺 ↾s 𝑆 ) ∈ Grp ) )
3 2 simp2bi ⊢ ( 𝑆 ∈ ( SubGrp ‘ 𝐺 ) → 𝑆 ⊆ 𝐵 )