Metamath Proof Explorer


Theorem subneintrd

Description: Introducing subtraction on both sides of a statement of inequality. Contrapositive of subcand . (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses negidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
pncand.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
subaddd.3 ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
subneintrd.4 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
Assertion subneintrd ( 𝜑 → ( 𝐴 − 𝐵 ) ≠ ( 𝐴 − 𝐶 ) )

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 pncand.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 subaddd.3 ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
4 subneintrd.4 ⊢ ( 𝜑 → 𝐵 ≠ 𝐶 )
5 1 2 3 subcanad ⊢ ( 𝜑 → ( ( 𝐴 − 𝐵 ) = ( 𝐴 − 𝐶 ) ↔ 𝐵 = 𝐶 ) )
6 5 necon3bid ⊢ ( 𝜑 → ( ( 𝐴 − 𝐵 ) ≠ ( 𝐴 − 𝐶 ) ↔ 𝐵 ≠ 𝐶 ) )
7 4 6 mpbird ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) ≠ ( 𝐴 − 𝐶 ) )