Metamath Proof Explorer


Theorem subscld

Description: Closure law for surreal subtraction. (Contributed by Scott Fenton, 5-Feb-2025)

Ref Expression
Hypotheses subscld.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
subscld.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
Assertion subscld ( 𝜑 → ( 𝐴 -s 𝐵 ) ∈ No )

Proof

Step Hyp Ref Expression
1 subscld.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 subscld.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
3 subscl ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 -s 𝐵 ) ∈ No )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 -s 𝐵 ) ∈ No )