Metamath Proof Explorer


Theorem subsf

Description: Function statement for surreal subtraction. (Contributed by Scott Fenton, 17-May-2025)

Ref Expression
Assertion subsf -s : ( No × No ) ⟶ No

Proof

Step Hyp Ref Expression
1 negscl ⊢ ( 𝑦 ∈ No → ( -us ‘ 𝑦 ) ∈ No )
2 addscl ⊢ ( ( 𝑥 ∈ No ∧ ( -us ‘ 𝑦 ) ∈ No ) → ( 𝑥 +s ( -us ‘ 𝑦 ) ) ∈ No )
3 1 2 sylan2 ⊢ ( ( 𝑥 ∈ No ∧ 𝑦 ∈ No ) → ( 𝑥 +s ( -us ‘ 𝑦 ) ) ∈ No )
4 3 rgen2 ⊢ ∀ 𝑥 ∈ No ∀ 𝑦 ∈ No ( 𝑥 +s ( -us ‘ 𝑦 ) ) ∈ No
5 df-subs ⊢ -s = ( 𝑥 ∈ No , 𝑦 ∈ No ↦ ( 𝑥 +s ( -us ‘ 𝑦 ) ) )
6 5 fmpo ⊢ ( ∀ 𝑥 ∈ No ∀ 𝑦 ∈ No ( 𝑥 +s ( -us ‘ 𝑦 ) ) ∈ No ↔ -s : ( No × No ) ⟶ No )
7 4 6 mpbi ⊢ -s : ( No × No ) ⟶ No