Theorem supcl

Description: A supremum belongs to its base class (closure law). See also supub and suplub . (Contributed by NM, 12-Oct-2004)

	Ref	Expression
Hypotheses	supmo.1	⊢ ( 𝜑 → 𝑅 Or 𝐴 )
	supcl.2	⊢ ( 𝜑 → ∃ 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) )
Assertion	supcl	⊢ ( 𝜑 → sup ( 𝐵 , 𝐴 , 𝑅 ) ∈ 𝐴 )

Proof

Step	Hyp	Ref	Expression
1		supmo.1	⊢ ( 𝜑 → 𝑅 Or 𝐴 )
2		supcl.2	⊢ ( 𝜑 → ∃ 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) )
3	1	supval2	⊢ ( 𝜑 → sup ( 𝐵 , 𝐴 , 𝑅 ) = ( ℩ 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) ) )
4	1 2	supeu	⊢ ( 𝜑 → ∃! 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) )
5		riotacl	⊢ ( ∃! 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) → ( ℩ 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) ) ∈ 𝐴 )
6	4 5	syl	⊢ ( 𝜑 → ( ℩ 𝑥 ∈ 𝐴 ( ∀ 𝑦 ∈ 𝐵 ¬ 𝑥 𝑅 𝑦 ∧ ∀ 𝑦 ∈ 𝐴 ( 𝑦 𝑅 𝑥 → ∃ 𝑧 ∈ 𝐵 𝑦 𝑅 𝑧 ) ) ) ∈ 𝐴 )
7	3 6	eqeltrd	⊢ ( 𝜑 → sup ( 𝐵 , 𝐴 , 𝑅 ) ∈ 𝐴 )