Metamath Proof Explorer
Description: A syllogism deduction with conjoined antecedents. (Contributed by NM, 24-Feb-2005) (Proof shortened by Wolf Lammen, 6-Apr-2013)
|
|
Ref |
Expression |
|
Hypotheses |
syldan.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 ) |
|
|
syldan.2 |
⊢ ( ( 𝜑 ∧ 𝜒 ) → 𝜃 ) |
|
Assertion |
syldan |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜃 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
syldan.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 ) |
| 2 |
|
syldan.2 |
⊢ ( ( 𝜑 ∧ 𝜒 ) → 𝜃 ) |
| 3 |
|
simpl |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜑 ) |
| 4 |
3 1 2
|
syl2anc |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜃 ) |