Metamath Proof Explorer


Theorem syldc

Description: Syllogism deduction. Commuted form of syld . (Contributed by BJ, 25-Oct-2021)

Ref Expression
Hypotheses syld.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
syld.2 ⊢ ( 𝜑 → ( 𝜒 → 𝜃 ) )
Assertion syldc ( 𝜓 → ( 𝜑 → 𝜃 ) )

Proof

Step Hyp Ref Expression
1 syld.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
2 syld.2 ⊢ ( 𝜑 → ( 𝜒 → 𝜃 ) )
3 1 2 syld ⊢ ( 𝜑 → ( 𝜓 → 𝜃 ) )
4 3 com12 ⊢ ( 𝜓 → ( 𝜑 → 𝜃 ) )